In ∆abc, s-a/∆=1/8, s-b/∆=1/12, s-c/∆=1/24 , find the value of b?

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Spacspade · Answer

I’m assuming your question is (s-a)/(delta)=1/8 and so on.. So multiply the 3 equations and you will get (delta).s=8*12*24 then find whatever you require!

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In ∆abc, s-a/∆=1/8, s-b/∆=1/12, s-c/∆=1/24 , find the value of b?

In ∆abc, s-a/∆=1/8, s-b/∆=1/12, s-c/∆=1/24 , find the value of b?

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In ∆abc, s-a/∆=1/8, s-b/∆=1/12, s-c/∆=1/24 , find the value of b?

In ∆abc, s-a/∆=1/8, s-b/∆=1/12, s-c/∆=1/24 , find the value of b?

1 Answers

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Other Related Questions on Trigonometry

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