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In a triangle (r1-r)/a + (r2-r)/b= where r1,r2 are exradii and r is in radii

In a triangle (r1-r)/a + (r2-r)/b= where r1,r2 are exradii and r is in radii

Grade:11

1 Answers

Arun
25750 Points
6 years ago
Dear Ayushi
 
r1 = delta / s- a
r2 = delta / s-b
Now
 
(delta/ s-a  - delta /s)/a + (delta /s-b  - delta /s)/b
= delta(a/s(s-a))/a + delta (b/s (s-a))/b
= delta / s (s-a) + dekta / s (s-b)
= r1/s + r2/s
= (r1 + r2)/s
 
 
Regards
Arun (askIITians forum expert)

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