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In a triangle ABC, the angles A, B, C are in A.P. Show that 2 cos [(A-C)/2] = a+c/sqrt(a^2-ac+c^2)

In a triangle ABC, the angles A, B, C are in A.P. Show that 2 cos [(A-C)/2] = a+c/sqrt(a^2-ac+c^2)
 
 

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2 Answers

Arun Kumar IIT Delhi
askIITians Faculty 256 Points
8 years ago
Hi




Thanks & Regards, Arun Kumar, Btech,IIT Delhi, Askiitians Faculty
Akshay Chaudhari
35 Points
8 years ago
By cosine law i.e. 2accosB=a^2+c^2-b^2
RHS=a+c/b
By sine law i.e. a=2RSinA,and similarly
Further applying Formula of SinA + SinC in LHS
Hence LHS=RHS
 

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