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In a triangle ABC,prove that sin3Asin(B-C)+sin3Bsin(C-A)+sin3Csin(A-B)=0 In a triangle ABC,prove that sin3Asin(B-C)+sin3Bsin(C-A)+sin3Csin(A-B)=0
Dear studentPlease approach using( Sin A/ a) = ( sin B / b ) = ( sin C / c) = kExpand sin 3A = 3ak - 4 ( ak)^3If doubt still persists kindly revert for complete solutionRegards
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