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In a triangle
a^2+b^2+c^2-ac-sqrt3*ab=0
then the triangle is

Leo Pixie , 10 Years ago
Grade 9
anser 2 Answers
Arun Kumar

Last Activity: 10 Years ago

Hello Student,
\\a^2+b^2+c^2-ac-root3 *ab=0 \\$using quadratic formulae$ \\a={c+b\sqrt3 \pm \sqrt{-b^2-3c^2+2bc\sqrt3} \over 2} \\a={c+b\sqrt3 \pm \sqrt{-(b-c\sqrt3)^2} \over 2} \\=>b=c\sqrt3 \\=>a=2c \\ {a \over 1}={b \over \sqrt3}={c \over 1} \\=>sinA=1
Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty

Leo Pixie

Last Activity: 10 Years ago

Great method

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