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In a traingle ABC, 3 sinA+4 cosB=6 and 4 sinB+3cosA=1, then find angle C in degrees.

In a traingle ABC, 3 sinA+4 cosB=6 and 4 sinB+3cosA=1, then find angle C in degrees.

Grade:10

1 Answers

Arun
25750 Points
6 years ago

C=30 DEGREE ONLY

WHY C CAN'T BE 150?

If C is 150 then A +B must be 30

So sinA is maximum when A takes value very close to 30 and cos B is maximum when B takes value very close to 0

In that case 3sinA + 4cosB can take maximum value 3(1/2)+4(1) =5.5 which is less than 6, it's given that 3sinA + 4 cosB=6 ..So c =150 not possible.

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