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if x^2 – 9 + | x+ sin a | < 0 then find the set of value of a that satisfy the given inequality
|x+sina|>0 for all x,x^2-9 <0 for -3<x>3since the function is symmetric,for x>0x^2-9+x+sin(a)taking most least value of sin(a)=-1x^2+x-10=0(x+.5)^2-10.25=0x+.5= sqrt(10.25) =3.2-.5=2.7so function will satisfy inequality for -2.7<x>2.7sher mohammadb.tech, iit delhi
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