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saurabh Grade: 12th pass
        
if x^2 – 9 + | x+ sin a | < 0 then find the set of value of a that satisfy the given inequality
3 years ago

Answers : (2)

Sher Mohammad
IIT Delhi
askIITians Faculty
174 Points
										|x+sina|>0 for all x,
x^2-9 <0 for -3<x>3

since the function is symmetric,

for x>0
x^2-9+x+sin(a)
taking most least value of sin(a)=-1

x^2+x-10=0
(x+.5)^2-10.25=0
x+.5= sqrt(10.25)
=3.2-.5=2.7

so function will satisfy inequality for -2.7<x>2.7

sher mohammad
b.tech, iit delhi


3 years ago
saurabh
12 Points
										
thank you
3 years ago
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