if x^2 – 9 + | x+ sin a | < 0 then find the set of value of a that satisfy the given inequality
if x^2 – 9 + | x+ sin a | < 0 then find the set of value of a that satisfy the given inequality
saurabh , 11 Years ago
Grade 12th pass
Trigonometry> if x^2 – 9 + | x+ sin a |...
2 AnswersSher Mohammad
|x+sina|>0 for all x,
x^2-9 <0 for -3<x>3
since the function is symmetric,
for x>0
x^2-9+x+sin(a)
taking most least value of sin(a)=-1
x^2+x-10=0
(x+.5)^2-10.25=0
x+.5= sqrt(10.25)
=3.2-.5=2.7
so function will satisfy inequality for -2.7<x>2.7
sher mohammad
b.tech, iit delhi
Approved Last Activity: 11 Years ago
saurabh
thank you
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