MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12
        
If the smallest radius of a circle passing through the intersection of x+ y2  + 2x = 0 and x - y = 0 , is r then value of 10r2  is equal to?
10 months ago

Answers : (1)

Arun
22578 Points
							
Dear student
 
Circle which have smallest radius willbhave that chord as diameter 
 
Hence
 
Find the points of intersection and then length this will be the diameter.
 
2 x² + 2x = 0
 
Hence
 
x = 0 and -1
 
Hence
 
Points are (0,0) and (-1, -1)
 
Hence diameter = sqrt (2)
 
Radius = sqrt (2) /2 = 1 /sqrt (2)
 
Hence 10r² = 10/2 = 5
10 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 31 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details