If the smallest radius of a circle passing through the intersection of x 2 + y 2 + 2x = 0 and x - y = 0 , is r then value of 10r 2 is equal to?

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Arun · Answer

Dear student Circle which have smallest radius willbhave that chord as diameter Hence Find the points of intersection and then length this will be the diameter. 2 x² + 2x = 0 Hence x = 0 and -1 Hence Points are (0,0) and (-1, -1) Hence diameter = sqrt (2) Radius = sqrt (2) /2 = 1 /sqrt (2) Hence 10r² = 10/2 = 5

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If the smallest radius of a circle passing through the intersection of x 2 + y 2 + 2x = 0 and x - y = 0 , is r then value of 10r 2 is equal to?

If the smallest radius of a circle passing through the intersection of x²+ y²+ 2x = 0 and x - y = 0 , is r then value of 10r²is equal to?

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If the smallest radius of a circle passing through the intersection of x 2 + y 2 + 2x = 0 and x - y = 0 , is r then value of 10r 2 is equal to?

If the smallest radius of a circle passing through the intersection of x2 + y2 + 2x = 0 and x - y = 0 , is r then value of 10r2 is equal to?

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If the smallest radius of a circle passing through the intersection of x²+ y²+ 2x = 0 and x - y = 0 , is r then value of 10r²is equal to?