 Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

If the smallest radius of a circle passing through the intersection of x+ y2  + 2x = 0 and x - y = 0 , is r then value of 10r2  is equal to?
10 months ago

Dear student

Circle which have smallest radius willbhave that chord as diameter

Hence

Find the points of intersection and then length this will be the diameter.

2 x² + 2x = 0

Hence

x = 0 and -1

Hence

Points are (0,0) and (-1, -1)

Hence diameter = sqrt (2)

Radius = sqrt (2) /2 = 1 /sqrt (2)

Hence 10r² = 10/2 = 5
10 months ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Other Related Questions on Trigonometry

View all Questions »  Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions