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`        If tanx + tan(x + pi/3) + tan(x – pi/3) = 3, find x`
7 months ago

Arun
23764 Points
```							tanx + {tanx + tanπ/3}/{1 - tanx.tanπ/3} + {tanx + tan2π/3}/{1 - tanx.tan2π/3} = 3=> tanx + {tanx + √3}/{1 - √3tanx} + {tanx - √3}/{1 + √3tanx} = 3=>  = 3=> tanx + {tanx + √3tan²x + √3 + 3tanx + tanx - √3tan²x - √3 + 3tanx}/{1 - 3tan²x} = 3=> tanx + {8tanx}/{1 - 3tan²x} = 3=> {tanx - 3tan³x + 8tanx}/{1 - 3tan²x} = 3=> {9tanx - 3tan³x}/{1 - 3tan²x} = 3=> 3{tanx - 3tan³x}/{1 - 3tan²x} = 3we know:- tan3A = {tanA - 3tan³A}/{1 - 3tan²A}therefore, tan3x = 3/3=> tan3x = 1 hence x  = 45/3
```
7 months ago
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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions