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We know that a+b+c=p
So tan (a+b-c)/tan(a-b+c) =tanc/tanb
Tan(p-2c)/tan(p-2b) =tanc/tanb
tan 2c/tan 2b =tanc/tanb
{2tanc/(1-tan2c)}/{2tanb/(1-tan2b)} =tanc/tanb
(1-tan2b)/(1-tan2c) =1
Tan2b=tan2c
Tanb=tanc
Tanb=tanc or tan(p+c)
b=c or p+c
b-c=0 or p
so sin(b-c) = sin0 or p
sin(b-c) =0 or p
Hence Ans is 0 orp
Thanks & Regards
Rinkoo Gupta
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