if tan(A-B)=1, sec(A+B)=2/sq. root 3, then find the smallest positive value of B?
if tan(A-B)=1, sec(A+B)=2/sq. root 3, then find the smallest positive value of B?
PIUS RANJAN PADHI , 8 Years ago
Grade 11
Trigonometry> if tan(A-B)=1, sec(A+B)=2/sq. root 3, the...
1 Answers
Arun
a-b=nPi+ Pi/41/cos(a+b)=sec(a+b)=2/root 3cos(a+b)=root 3/2a+b=2nPi+Pi/6a=2nPi+1/2(Pi/4+Pi/6)b=2nPi+1/2(Pi/6-Pi/4)for n=0,smallest value of a=1/2(Pi/4+Pi/6)smallest value of b=1/2(Pi/6-Pi/4)
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