Sayam
Last Activity: 8 Years ago
Tan{(π/4)+x}+tan{(π/4)-x}=anow, Tan^3{(π/4)+x}+tan^3{(π/4)-x}=
*Tan{(π/4)+x} by applying a3+b3=(a+b)(a2-ab+b2)Tan{(π/4)+x}Tan2{(π/4)-x}-Tan2{(π/4)+x}+[Tan{(π/4)+x}+tan{(π/4)-x}][=a[Tan2{(π/4)+x}+Tan2{(π/4)-x}-1]
=a[[Tan{(π/4)+x}+tan{(π/4)-x}]2-3]
=a[a2-3]=a3-3a