Soumendu Majumdar
Last Activity: 6 Years ago
root(sin x) + cos x = 0
implies sin x = cos^2 x …........by squaring both sides
implies sin^2 x + sin x – 1 = 0.........by using cos^2 x = 1 – sin^2 x
Now using shreedharacharya formula to find roots of a quadratic equation
you get
sin x = ( -1 ± root(5) )/2
now sin x= (-1 – root(5) )/2 is less than – 1 but sin x always lies within – 1 and 1
so sin x = ( root(5) – 1 )/2
Hope it helps....