If sinA + sin 2 A=1 and a cos 12 A + b cos 8 A + c cos 6 A - 1= 0 then prove that b + c/a + b = 3

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Arun · Answer

sin@+sin^2@=1 =>sin@=1-sin^2@=cos^2@ Now we know cos^12@+3cos^10@+3cos^8@+cos^6@-1 = 0 Hence Now find a, b, c, d and then find answer. Regards

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If sinA + sin 2 A=1 and a cos 12 A + b cos 8 A + c cos 6 A - 1= 0 then prove that b + c/a + b = 3

If sinA + sin²A=1 and a cos¹²A + b cos⁸ A + c cos⁶ A - 1= 0 then prove that b + c/a + b = 3

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If sinA + sin 2 A=1 and a cos 12 A + b cos 8 A + c cos 6 A - 1= 0 then prove that b + c/a + b = 3

If sinA + sin2A=1 and a cos12A + b cos8 A + c cos6 A - 1= 0 then prove that b + c/a + b = 3

1 Answers

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If sinA + sin²A=1 and a cos¹²A + b cos⁸ A + c cos⁶ A - 1= 0 then prove that b + c/a + b = 3