If sin3a=5sinb then find the value of tan [(a+b)/2] / tan[(a-b)/2]. Please explain with steps.

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Arun · Answer

Dear Purva 3sina=5sinb rearranging it (sina/sinb)=(5/3) now applying componendo and dividendo rule we get (sina+sinb)/(sina-sinb)=4 now using the identities of trigonometry we get (2sin((a+b)/2)cos((a-b)/2) )/( 2cos((a+b)/2)sin((a-b)/2))=4 this becomes (tan((a+b)/2) )/( tan((a-b)/2)=4 Hope it helps Regards Arun (askIITians forum expert)

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If sin3a=5sinb then find the value of tan [(a+b)/2] / tan[(a-b)/2]. Please explain with steps.

If sin3a=5sinb then find the value of tan [(a+b)/2] / tan[(a-b)/2]. Please explain with steps.

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