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```
if sin x +sin^2 x + sin^3 x = 1 then cos^6 x - 4 cos^4 x +9cos^2 x = ?

```
6 years ago

```							sinx+sin^3x=1-sin^2xsinx+sin^3x=cos^2xsinx(1+sin^2x)=cos^2xsinx(1+1-cos^2x)=cos^2xsinx(2-cos^2x)=cos^2xsquaring both sidessin^2x(2-cos^2x)^2=cos^4xsin^2x(4+cos^4x-4cos^2x)=cos^4x(1-cos^2x)(4+cos^4x-4cos^2x)=cos^4x4+cos^4x-4cos^2x-4cos^2x-cos^6x+4cos^4x=cos^4x4-cos^6x-8cos^2x+4cos^4x=0cos^6x-4cos^4x+8cos^2x=4 Thanks & RegardsRinkoo GuptaaskIITians Faculty
```
6 years ago
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