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`        If sin theta. Cos theta =k then sin theta + cos theta =`
2 years ago

```							Let theta be @ for simpler in writingLet`s sin@ + cos@=m then after doing both side squaring we get 1+2k=m^2  so therefore m=(1+2k)^1/2
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2 years ago
```							Let`s assume sintheta as a and costtheta as b then He given ab=k then you have to find a+b(a+b)^2-2ab=(a^2+b^2-
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2 years ago
```							[Sin(tita)+cos(tita)]^2=sin^2(tita)+cos^2(tita)+2.sin(tita) .cos (tita) =1+2.kSo,sin (tita)+cos(tita) = √1+2kSince we know thatSin^2(tita)+cos^2(tita) = 1Given sin(tita).cos(tita) = k
```
one year ago
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