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If sin theta = a-b/a+b then tan(45°-theta/2)= 1)√a/b 2)√b/a 3)√ab 4)√a+b

If sin theta = a-b/a+b then tan(45°-theta/2)=
1)√a/b
2)√b/a
3)√ab
4)√a+b

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Grade:10

1 Answers

Aditya Gupta
2081 Points
4 years ago
hello nikhil this is an easy ques. let theta= 2x.
now given that sin 2x = a-b/a+b and we have to find y= tan(45° – x)= (1 – t)/(1+t).....(1) where t= tanx.
we now use another standard formula: sin 2x= 2t/(1+t^2) where t= tanx as already mentioned.
so we have 2t/(1+t^2)= a-b/a+b.......(2)
now, from (1), we can rearrange and write t= 2/(y+1) – 1. substitute this value of t in (2).
after a bit of cancellations and rearrangement you shall obtain
(a+b)(1 – y^2)= (a – b)(1 + y^2)
or y^2= b/a
or y= √b/a
option 2 is correct
kindly approve :)

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