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Grade: 10
        If secA-tanA = root2 tanA then show that secA+ tanA = root2 secA
3 years ago

Answers : (2)

Harsh Patodia
IIT Roorkee
askIITians Faculty
906 Points
							PFA
228-460_7.PNG
3 years ago
Fathima Nazar
11 Points
							Given: secA - tanA = √2 tanATo prove: secA+tanA=√2secAProof:      SecA-tanA= √2tanA   =>secA-tanA -√2tanA =0   => -secA+tanA+√2tanA=0   => tanA+√2tanA= secA            tanA(1+√2)=secA                      tanA =secA/1+√2On rationalizing we gettanA= secA-√2secA/-1 Substituting this value of tanAWe getSecA+tanA=secA+  secA-√2secA /-1On taking LCM = -secA+secA -√2secA/-1-secA and+secA get cancelled=-√2secA/-1Negative sign will get cancelled=√2secAHence proved
						
2 years ago
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