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if k1=tan27x – tanx and k2=(sinx/cos3x)+(sin3x/cos9x)+(sin9x/cos27x), then:
  1. k1=2k2
  2. k1=k2+4
  3. k1=k2
  4. none of these

Mohit Bhavsar , 7 Years ago
Grade 11
anser 1 Answers
Saurabh Koranglekar

Last Activity: 5 Years ago

Dear student

Please consider x = 0 and pi/4

Relation obtained would be a) k1= 2k2

Regards

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