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if k1=tan27x – tanx and k2=(sinx/cos3x)+(sin3x/cos9x)+(sin9x/cos27x), then: k1=2k2 k1=k2+4 k1=k2 none of these

if k1=tan27x – tanx and k2=(sinx/cos3x)+(sin3x/cos9x)+(sin9x/cos27x), then:
  1. k1=2k2
  2. k1=k2+4
  3. k1=k2
  4. none of these

Grade:11

1 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
2 years ago
Dear student

Please consider x = 0 and pi/4

Relation obtained would be a) k1= 2k2

Regards

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