Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

if in triangle ABC a=6,b=3 and cos(A-B)=4/5 then its area is

if in triangle ABC a=6,b=3 and cos(A-B)=4/5 then its area is
 

Grade:9

1 Answers

Arun
25763 Points
3 years ago
Dear Hemant
 
cos (A-B) = (1 -tan²(A-B)/2)/(1+tan²(A-B)/2) = 4/5
On cross multiplication and then solving
 
tan²(A-B)/2 = 1/9
tan(A-B)/2 = 1/3
 
 
Hence
(a-b) cot(C/2)/(a+b) = 1/3
On solving
 
Cot(c/2) = 1
C/2 = 45°
C = 90°
Hence it is a right angle triangle
 
 
Now area = (1/2)*3*6 = 9 square units
 
 
Regards
Arun (askIITians forum expert)

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free