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If in a triangle ABC a Cos*2(c/2)+cos*2(A/2)=3b/2 then the sides a,b,c are If in a triangle ABC a Cos*2(c/2)+cos*2(A/2)=3b/2 then the sides a,b,c are
we know cosC=2cos^2(C/2)-1 so, a(1+cosC)/2+c(1+cosA)/2=3b/2 a+acosC+c+ccosA=3b a+c+(acosC+ccosA)=3b Using By projection formula: (acosC+ccosA)=b a+c+b=3b a+c=2bThis shows that a,b,c are in A.P.thank you. my name : ashu mehta (bupp), (sirsa)
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