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If in a triangle ABC a Cos*2(c/2)+cos*2(A/2)=3b/2 then the sides a,b,c are

A , 7 Years ago
Grade 12th pass
anser 1 Answers
ALL IN ONE

Last Activity: 7 Years ago

we know cosC=2cos^2(C/2)-1
 
so, a(1+cosC)/2+c(1+cosA)/2=3b/2
 
a+acosC+c+ccosA=3b
 
a+c+(acosC+ccosA)=3b
 
Using By projection formula: (acosC+ccosA)=b
 
a+c+b=3b
 
a+c=2b
This shows that a,b,c are in A.P.
thank you. my name : ashu mehta (bupp), (sirsa)
 
 

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