saimohan
Last Activity: 8 Years ago
cosec theta-sin theta=m
1/sin theta-sin theta=m
1-sinsquare theta/sin theta=m
cos square theta/sin theta=m (1)
sec theta-cos theta=n
1/cos theta-cos theta=n
1-cos square theta/cos theta=n
sin square theta/cos theta=n (2)
from 1&2
cos square theta/sin theta=sin square theta /cos theta
by cross multiply
cos3 theta-sin3 theta=0
cos theta*sin theta(cos2 theta-sin2 theta)=0
cos theta.sin theta(1)=0
the relation is m*n
