If cos(A-B)+cos(B-A)+cos(C-A) =-3/2 then prove cosA+cosB+cosC=sinA+sinB+sinC=0

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Saurabh Koranglekar · Answer

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If cos(A-B)+cos(B-A)+cos(C-A) =-3/2 then prove cosA+cosB+cosC=sinA+sinB+sinC=0

If cos(A-B)+cos(B-A)+cos(C-A) =-3/2 then prove cosA+cosB+cosC=sinA+sinB+sinC=0

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If cos(A-B)+cos(B-A)+cos(C-A) =-3/2 then prove cosA+cosB+cosC=sinA+sinB+sinC=0

If cos(A-B)+cos(B-A)+cos(C-A) =-3/2 then prove cosA+cosB+cosC=sinA+sinB+sinC=0

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