0

Guest

Courses New

IF COS*4X/A+SIN*4/B=1/A+B SHOW THAT COS*8/A*3+SIN*8/B*3=(1/A+B)*3

IF COS*4X/A+SIN*4/B=1/A+B SHOW THAT COS*8/A*3+SIN*8/B*3=(1/A+B)*3

Grade:12th pass

2 Answers

Latika Leekha
askIITians Faculty 165 Points
8 years ago
Hello student,
We know that cos4x = (cos2x)2 = (1 – sin2x)2 = 1 + sin4x – 2sin2x
So, sin4x / b + cos4x/a = 1/(a+b)

242-133_forum 15th june.png242-1898_Forum 15th June (2).png
So, cos8x/a3 + sIn 8x/b3 = (1/a+b)3
Kushagra Madhukar
askIITians Faculty 628 Points
3 years ago
Dear student,
 
Write cosx in terms of sinx and then simplify to obtain the value of sinx
Later using this find the value of cosx
obtain both sin8x and cos8x and then substitute to get the answer
The final answer will be
cos8x/a3 + sIn 8x/b3 = 1/(a+b)3
Refer to the above answer for a more complete solution.
 
Thanks and regards,
Kushagra

Think You Can Provide A Better Answer ?

Other Related Questions on Trigonometry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More