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IF COS*4X/A+SIN*4/B=1/A+B SHOW THAT COS*8/A*3+SIN*8/B*3=(1/A+B)*3

Bylapudi Kanakaraju , 10 Years ago
Grade 12th pass
anser 2 Answers
Latika Leekha
Hello student,
We know that cos4x = (cos2x)2 = (1 – sin2x)2 = 1 + sin4x – 2sin2x
So, sin4x / b + cos4x/a = 1/(a+b)

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So, cos8x/a3 + sIn 8x/b3 = (1/a+b)3
Last Activity: 10 Years ago
Kushagra Madhukar
Dear student,
 
Write cosx in terms of sinx and then simplify to obtain the value of sinx
Later using this find the value of cosx
obtain both sin8x and cos8x and then substitute to get the answer
The final answer will be
cos8x/a3 + sIn 8x/b3 = 1/(a+b)3
Refer to the above answer for a more complete solution.
 
Thanks and regards,
Kushagra
Last Activity: 5 Years ago
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