If coax is expressed in the form of acos(4x)+bcos(2x)+c, where a,b and c are constant then the value of (a+b+c), is equal to(A)1. (B) 11/8. (C) 7/4. (D)2.

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Saurabh Koranglekar · Answer

Dear student Put x = 0 Cos x = 1 Cos 4 x = 1 Cos 2x = 1 a+b+c = 1 Regards

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If coax is expressed in the form of acos(4x)+bcos(2x)+c, where a,b and c are constant then the value of (a+b+c), is equal to(A)1. (B) 11/8. (C) 7/4. (D)2.

If coax is expressed in the form of acos(4x)+bcos(2x)+c, where a,b and c are constant then the value of (a+b+c), is equal to(A)1. (B) 11/8. (C) 7/4. (D)2.

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If coax is expressed in the form of acos(4x)+bcos(2x)+c, where a,b and c are constant then the value of (a+b+c), is equal to(A)1. (B) 11/8. (C) 7/4. (D)2.

If coax is expressed in the form of acos(4x)+bcos(2x)+c, where a,b and c are constant then the value of (a+b+c), is equal to(A)1. (B) 11/8. (C) 7/4. (D)2.

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