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if a*sin^(-1)x – b*cos^(-1)x=c thena*sin^(-1)x + b*cos^(-1)x=????
replace x by -x in given eq.asin-1(-x) -bcos-1(-x) =c-asin-1(x)-bcos-1(x)=casin-1(x)+bcos-1(x)= -cThanks & RegardsRinkoo GuptaAskIITians Faculty
but options are 0 [(pi)ab+c(b-a)]/(a+b) pi/2 [(pi)ab+c(a-b)]/(a+b)
asin^-1 x - bcos^-1 x = c We have bsin^-1 x + bcos^-1 x = b(pi)/2(a+b)sin^-1 x = b(pi)/2 + csin^-1 x =( b(pi)/2 + c)/a+ bcos^-1 x= [(pi)ab + c(a-b)]/a+b
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