0

Guest

Courses New

if a cos 2 theta + bsin 2 theta =c has a and b as its solution,then prove that tan a +tan b = 2b/a+b

if a cos 2 theta + bsin 2 theta =c has a and b as its solution,then prove that tan a +tan b = 2b/a+b

Grade:11

1 Answers

manish
42 Points
6 years ago
Acos 2theta+ bsin 2theta=c=> a (1-tan^2 theta /1+tan^2 theta)+ b(2tan theta/ 1+tan ^2 theta)=c=>(-a-c)tan^2theta + 2btantheta+ a-c=0=> tan a+ tan b= -2 b/(-a-c)=2b/a+cSince a and bare the roots of the equation and sum of roots is the negative ratio of coefficients of x by coefficients of x^2Manish kumar panda

Think You Can Provide A Better Answer ?

Other Related Questions on Trigonometry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More