Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

if a cos 2 theta + bsin 2 theta =c has a and b as its solution,then prove that tan a +tan b = 2b/a+b

if a cos 2 theta + bsin 2 theta =c has a and b as its solution,then prove that tan a +tan b = 2b/a+b

Grade:11

1 Answers

manish
42 Points
4 years ago
Acos 2theta+ bsin 2theta=c=> a (1-tan^2 theta /1+tan^2 theta)+ b(2tan theta/ 1+tan ^2 theta)=c=>(-a-c)tan^2theta + 2btantheta+ a-c=0=> tan a+ tan b= -2 b/(-a-c)=2b/a+cSince a and bare the roots of the equation and sum of roots is the negative ratio of coefficients of x by coefficients of x^2Manish kumar panda

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free