if A+B=pi/2, where A,B0, then the maimum value of sinA + sinB is equal to

Question

if A+B=pi/2, where A,B>0, then the maimum value of sinA + sinB is equal to

Suraj Singh · Answer

Hy darshini A+B=pi/2... Therefore A=pi/2 - B.. We have to max value of SinA+SinB.. Putting tha above value it comes SinA+CosB whose maximum value is 1/root 2.. Hope U like it..

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if A+B=pi/2, where A,B>0, then the maimum value of sinA + sinB is equal to

if A+B=pi/2, where A,B>0, then the maimum value of sinA + sinB is equal to

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if A+B=pi/2, where A,B>0, then the maimum value of sinA + sinB is equal to

if A+B=pi/2, where A,B>0, then the maimum value of sinA + sinB is equal to

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Other Related Questions on Trigonometry

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