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`        If A,B,C are angles of a triangle such that Sin2A+Sin2B+Sin2c= constant. Then show that dA/dB= tan B – tan C/tan C -tan A.`
one year ago

1717 Points
```							A+B+C= constor dA+dB+dC= 0and Sin2A+Sin2B+Sin2c= constantdifferentiate and substitute dc=  – (dA+dB)we getdA/dB= (sin2B- sin2C)/(sin2C- sin2A)but (sin2B- sin2C)/(sin2C- sin2A)= (tan B – tan C)/(tan C -tan A) [ you can prove this by using sinx-siny formula and writing tanx=sinx/cosx]
```
one year ago
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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions