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Grade: 12th pass
        
If A,B,C are angles of a triangle such that Sin2A+Sin2B+Sin2c= constant. Then show that dA/dB= tan B – tan C/tan C -tan A.
one month ago

Answers : (1)

Aditya Gupta
713 Points
							
A+B+C= const
or dA+dB+dC= 0
and Sin2A+Sin2B+Sin2c= constant
differentiate and substitute dc=  – (dA+dB)
we get
dA/dB= (sin2B- sin2C)/(sin2C- sin2A)
but (sin2B- sin2C)/(sin2C- sin2A)= (tan B – tan C)/(tan C -tan A) [ you can prove this by using sinx-siny formula and writing tanx=sinx/cosx]
 
one month ago
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