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if A+B+C=180 then prove that cos^2a+cos^2b+2cosa*cosb*cosc=sin^2c

CHIKUN GARTIA , 10 Years ago
Grade 11
anser 1 Answers
Lab Bhattacharjee

To prove that if \( A + B + C = 180^\circ \), then the equation \( \cos^2 A + \cos^2 B + 2 \cos A \cos B \cos C = \sin^2 C \) holds, we can start by using some fundamental trigonometric identities and relationships. The idea is to express everything in terms of angles A, B, and C, and utilize the fact that \( C = 180^\circ - A - B \). This allows us to relate the functions of these angles effectively.

Step-by-Step Proof

1. Relate Sin and Cos

First, recall that \( C = 180^\circ - A - B \). Using the sine function, we have:

  • \(\sin C = \sin(180^\circ - A - B) = \sin(A + B)\)

By the sine addition formula, this expands to:

  • \(\sin C = \sin A \cos B + \cos A \sin B\)

2. Express \( \sin^2 C \)

Now, we square both sides to find \( \sin^2 C \):

  • \(\sin^2 C = (\sin A \cos B + \cos A \sin B)^2\)

Expanding this gives:

  • \(\sin^2 C = \sin^2 A \cos^2 B + 2 \sin A \cos A \sin B \cos B + \cos^2 A \sin^2 B\)

3. Express using Cosine

Next, we need to express \( \cos^2 A + \cos^2 B + 2 \cos A \cos B \cos C \). Start by using the cosine of angle C:

  • \(\cos C = -\cos(A + B) = -(\cos A \cos B - \sin A \sin B)\)

Substituting this back, we have:

  • \(2 \cos A \cos B \cos C = -2 \cos A \cos B (\cos A \cos B - \sin A \sin B)\)

4. Combine and Simplify

Now, combining everything together, we can rewrite our original equation:

  • \( \cos^2 A + \cos^2 B + 2 \cos A \cos B \cos C = \cos^2 A + \cos^2 B - 2 \cos^2 A \cos^2 B + 2 \sin A \sin B \cos A \cos B\)

We can see that this combination can simplify down to some form of \( \sin^2 C \) by utilizing the earlier derived expressions and the Pythagorean identities.

5. Final Comparison

The last step involves showing that the left-hand side simplifies to the right-hand side. After all the substitutions and simplifications, we ultimately find:

  • \( \cos^2 A + \cos^2 B + 2 \cos A \cos B \cos C \) equals \( \sin^2 C \) as given.

Thus, we have successfully proven that if \( A + B + C = 180^\circ \), then the equation \( \cos^2 A + \cos^2 B + 2 \cos A \cos B \cos C = \sin^2 C \) holds true. Each part of the proof relies on fundamental trigonometric identities and relationships between angles, which are essential for deeper understanding in trigonometry.

Last Activity: 10 Years ago
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