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If A+B+C = 180then cos3A + cos3B + cos3Ca. 1 - 4 sin3A/2sin3B/2sin3C/2b. 4 cos3A/2cos3B/2cos3C/2c. 1-4 cos3A/2cos3B/2cos3C/2d. -4 cos3A/2cos3B/2cos3C/2

mahesh , 6 Years ago
Grade 12
anser 1 Answers
Shreshth graak

Last Activity: 6 Years ago

Cos3A+cos3B+cos3C 
2[cos3(A+B)/2]cos3(A-B)/2 + cos3C
-2[sin3c/2]cos3(a-b)/2 + 1-sin²3c/2
1-2sin3c/2[cos3(a-b)/2 - sin3c/2
After solving this u git answer
 

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