Grade 12AlgebraIf A+B+C = 180 then cos3A + cos3B + cos3Ca. 1 - 4 sin3A/2sin3B/2sin3C/2b. 4 cos3A/2cos3B/2cos3C/2c. 1-4 cos3A/2cos3B/2cos3C/2 d. -4 cos3A/2cos3B/2cos3C/2 mahesh 7 Years agoGrade 12
Shreshth graak7 Years agoCos3A+cos3B+cos3C 2[cos3(A+B)/2]cos3(A-B)/2 + cos3C-2[sin3c/2]cos3(a-b)/2 + 1-sin²3c/21-2sin3c/2[cos3(a-b)/2 - sin3c/2After solving this u git answer