If a0,b x-0 + (root(1-cos 2ax))/sin bx is equal to _______ a (root2)/b -a (root2)/b |a|(root2)/|b| -|a|(root2)/|b| PLEASE EXPLAIN THE SOLUTION OF YOUR ANSWER

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If a>0,b x->0 + (root(1-cos 2ax))/sin bx is equal to _______ a (root2)/b -a (root2)/b |a|(root2)/|b| -|a|(root2)/|b| PLEASE EXPLAIN THE SOLUTION OF YOUR ANSWER

Aditya Gupta · Answer

root(1-cos 2ax)= root2*sinax limit is root2*a/b because lim x->0 + sinax/sinbx=a/b* lim x->0 + sinax/ax*bx/sinbx=a/b*1*1=a/b so, answer is root2*a/b

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If a>0,b x->0 + (root(1-cos 2ax))/sin bx is equal to _______ a (root2)/b -a (root2)/b |a|(root2)/|b| -|a|(root2)/|b| PLEASE EXPLAIN THE SOLUTION OF YOUR ANSWER

If a>0,b_x->0⁺ (root(1-cos 2ax))/sin bx is equal to _______
a (root2)/b
-a (root2)/b
|a|(root2)/|b|
-|a|(root2)/|b|

PLEASE EXPLAIN THE SOLUTION OF YOUR ANSWER

1 Answers

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If a>0,b x->0 + (root(1-cos 2ax))/sin bx is equal to _______ a (root2)/b -a (root2)/b |a|(root2)/|b| -|a|(root2)/|b| PLEASE EXPLAIN THE SOLUTION OF YOUR ANSWER

If a>0,bx->0+ (root(1-cos 2ax))/sin bx is equal to _______ a (root2)/b -a (root2)/b|a|(root2)/|b|-|a|(root2)/|b| PLEASE EXPLAIN THE SOLUTION OF YOUR ANSWER

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If a>0,b_x->0⁺ (root(1-cos 2ax))/sin bx is equal to _______
a (root2)/b
-a (root2)/b
|a|(root2)/|b|
-|a|(root2)/|b|

PLEASE EXPLAIN THE SOLUTION OF YOUR ANSWER