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Grade: 12
        
If a>0,bx->0+ (root(1-cos 2ax))/sin bx is equal to _______
-a (root2)/b
|a|(root2)/|b|
-|a|(root2)/|b|
 
PLEASE EXPLAIN THE SOLUTION OF YOUR ANSWER
one year ago

Answers : (1)

Aditya Gupta
1819 Points
							
root(1-cos 2ax)= root2*sinax
limit is root2*a/b because limx->0+sinax/sinbx=a/b*limx->0+sinax/ax*bx/sinbx=a/b*1*1=a/b
so, answer is root2*a/b 
one year ago
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