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`        If a>0,bx->0+ (root(1-cos 2ax))/sin bx is equal to _______ a (root2)/b -a (root2)/b|a|(root2)/|b|-|a|(root2)/|b| PLEASE EXPLAIN THE SOLUTION OF YOUR ANSWER`
one year ago

1819 Points
```							root(1-cos 2ax)= root2*sinaxlimit is root2*a/b because limx->0+sinax/sinbx=a/b*limx->0+sinax/ax*bx/sinbx=a/b*1*1=a/bso, answer is root2*a/b
```
one year ago
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Course Features

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Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions