If 2tana=3tanb then to prove sin(a+b)=5sin(a-b). Pls help in this ques because I have found no similar question on the net.

Question

SRC Jayanth · Answer

Given 2tana = 3 tanb 2 sina /cosa = 3 sinb / cosb by cross multiplying 2sina cosb = 3 sinb cosa multiplying 2 on both sides 4sina cosb = 6 sinb cosa 5sina cosb- sina cosb = 5sinb cosa + 1 sinb cosa bringing terms with integral coefficient – 5 on to one side then we get 5 (sina cosb - sinb cosa)= sina cosb + sinb cosa Which on applying transformation 5 sin (a -b)= sin(a+b) Hence we got the required.

Shashank Raut · Answer

2sinA/cosA = 3sinB/cosBcross multiple2sinAcosB=3sinBcosA2{sin(A+B)+sin(A-B)}= 3{sin(A+B)+sin(B-A)}Solve furtherTry to put more efforts because trigonometry will not come until you give maximum 20 minutes and minimum 15min

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If 2tana=3tanb then to prove sin(a+b)=5sin(a-b). Pls help in this ques because I have found no similar question on the net.

If 2tana=3tanb then to prove sin(a+b)=5sin(a-b). Pls help in this ques because I have found no similar question on the net.

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If 2tana=3tanb then to prove sin(a+b)=5sin(a-b). Pls help in this ques because I have found no similar question on the net.

If 2tana=3tanb then to prove sin(a+b)=5sin(a-b). Pls help in this ques because I have found no similar question on the net.

2 Answers

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