if [2^x+(22)^x+(222)^x]/[3^x+(33)^x+(333)^x] =9/4 then x equals

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Deepak Kumar Shringi · Answer

Amit · Answer

I Guess it should be 4/9 instead of 9/4..For this take out 2^x common from numerator and 3^x common from denominator and the common factor i.e; (1+11^x+111^x) gets cancelled out.. Hence x should be 2

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if [2^x+(22)^x+(222)^x]/[3^x+(33)^x+(333)^x] =9/4 then x equals

if [2^x+(22)^x+(222)^x]/[3^x+(33)^x+(333)^x] =9/4 then x equals

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if [2^x+(22)^x+(222)^x]/[3^x+(33)^x+(333)^x] =9/4 then x equals

if [2^x+(22)^x+(222)^x]/[3^x+(33)^x+(333)^x] =9/4 then x equals

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