if 0 0 is less than A is less than B is less than C is less than 90 0 then (sinA+sinB+sinC) divided by (cosA+cosB+cosC) lies between

Question

Saurabh Koranglekar · Answer

Dear student

Consider all angles equal

Given EQUATION can be reduced to 3sin A / 3 cos A

Also A varies in 0 to 90

So tan A varies in (0, infinity) intervel limits are open

This is because only one restriction is given for all angles

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if 0 0 is less than A is less than B is less than C is less than 90 0 then (sinA+sinB+sinC) divided by (cosA+cosB+cosC) lies between

if 0⁰ is less than A is less than B is less than C is less than 90⁰then (sinA+sinB+sinC) divided by (cosA+cosB+cosC) lies between

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if 0 0 is less than A is less than B is less than C is less than 90 0 then (sinA+sinB+sinC) divided by (cosA+cosB+cosC) lies between

if 00 is less than A is less than B is less than C is less than 900 then (sinA+sinB+sinC) divided by (cosA+cosB+cosC) lies between

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if 0⁰ is less than A is less than B is less than C is less than 90⁰then (sinA+sinB+sinC) divided by (cosA+cosB+cosC) lies between