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`        I need the full solution of the questions no. 24 plese help me finding this solution`
2 years ago Shashank Singh
57 Points
```							(sinx+cosx)^2= sin^2x+cos^2x + 2sinxcosxa^2= 1+2sinx cosx2sinxcosx= a^2-1............. (1)now (sin^2x+cos^2x)^3= sin^6x + 3sin^4xcos^2x + 3cos^4xsin^2x + cos^6x1= sin^6x + cos^6x +3sin^2xcos^2x(sin^2x+cos^2x)1=sin^6x+cos^6x+3sin^2xcos^2x............(2)putting the value from (1) in (2), we get1= sin^6x+cos^6x+ 3/4(a^2-1)^2therefore sin^6x+cos^6x= 1-3/4(a^2-1)^2.............  [hence proved]
```
2 years ago
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