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How to solve questions invoving trignometric equations ..as in question no. 21 ...any trick to solve such questions ..and all so tell question bo. 18

How to solve questions invoving trignometric equations ..as in question no. 21 ...any trick to solve such questions ..and all so tell question bo. 18

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Aditya Gupta
2081 Points
5 years ago
hi tanya, we know that sin^4x+cos^4x=1-2sin^2xcos^2x and  sin^6x+cos^6x=1-3sin^2xcos^2x , so, we get
cos^2x=(2sinxcosx)^2=sin^2(2x)
or cos^2x-sin^2(2x)=0
or cos4x=cos(pi/2)
or 4x=2npi ± pi/2
or x= npi/2 ± pi/8
so, in 0,2pi, number of distinct solutions are 8.

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