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How to solve questions invoving trignometric equations ..as in question no. 21 ...any trick to solve such questions ..and all so tell question bo. 18

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2 years ago

2074 Points
```							hi tanya, we know that sin^4x+cos^4x=1-2sin^2xcos^2x and  sin^6x+cos^6x=1-3sin^2xcos^2x , so, we getcos^2x=(2sinxcosx)^2=sin^2(2x)or cos^2x-sin^2(2x)=0or cos4x=cos(pi/2)or 4x=2npi ± pi/2or x= npi/2 ± pi/8so, in 0,2pi, number of distinct solutions are 8.
```
2 years ago
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### Course Features

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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions