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How to prove that cotA + cotB + cotC > 3^1/2 if A, B, C are the angle of the triangle ABC.

How to prove that cotA + cotB + cotC > 3^1/2 if A, B, C are the angle of the triangle ABC.

Grade:11

1 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
4 years ago
Dear student

This is no rule

Consider angle a,b,c be all equal to 0

Sum of individual cot angles = infinity > sqrt 3

But do not form triangle

Regards

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