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Grade: 11 

                        
how to find the general solution of sin3x=cos2x? please help
2 years ago

Answers : (1)

Arun
24738 Points 
							
Dear Purva
 
sin 3x = cos 2x
 
cos 2x = cos (pi/2 – 3x)
 
2x = 2n * pi ± (pi/2 – 3x)
 
take positive and negatuive sign and solve
2 years ago
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