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`        How do you solve this? The answer is A...........................................`
11 months ago

Devang
52 Points
```							    sin5$\dpi{80} {\color{Blue} \Theta }$  + sin2$\dpi{80} {\color{Blue} \Theta }$ – sin$\dpi{80} {\color{Blue} \Theta }$ /  cos5$\dpi{80} {\color{Blue} \Theta }$ + 2cos3$\dpi{80} {\color{Blue} \Theta }$ + 2cos2$\dpi{80} {\color{Blue} \Theta }$ + cos$\dpi{80} {\color{Blue} \Theta }$                = 2 * cos3$\dpi{80} {\color{Blue} \Theta }$ * sin2$\dpi{80} {\color{Blue} \Theta }$  + sin2$\dpi{80} {\color{Blue} \Theta }$ / 2 * cos3$\dpi{80} {\color{Blue} \Theta }$ * cos2$\dpi{80} {\color{Blue} \Theta }$ + 2cos3$\dpi{80} {\color{Blue} \Theta }$ + 2cos2$\dpi{80} {\color{Blue} \Theta }$               =  sin2$\dpi{80} {\color{Blue} \Theta }$ (2cos3$\dpi{80} {\color{Blue} \Theta }$ + 1) / 2cos3$\dpi{80} {\color{Blue} \Theta }$ ( cos2$\dpi{80} {\color{Blue} \Theta }$ + 1)  + 2cos2$\dpi{80} {\color{Blue} \Theta }$               =sin2$\dpi{80} {\color{Blue} \Theta }$ (2cos3$\dpi{80} {\color{Blue} \Theta }$ + 1)  / 2cos3$\dpi{80} {\color{Blue} \Theta }$ * 2cos2$\dpi{80} {\color{Blue} \Theta }$  + 2cos2$\dpi{80} {\color{Blue} \Theta }$                         (1 + cos2$\dpi{80} {\color{Blue} \Theta }$ = 2cos2$\dpi{80} {\color{Blue} \Theta }$ )               =sin2$\dpi{80} {\color{Blue} \Theta }$ (2cos3$\dpi{80} {\color{Blue} \Theta }$ + 1)  /  2cos2$\dpi{80} {\color{Blue} \Theta }$  (2cos3$\dpi{80} {\color{Blue} \Theta }$ + 1)               = 2 * sin $\dpi{80} {\color{Blue} \Theta }$ * cos$\dpi{80} {\color{Blue} \Theta }$ /  2cos2$\dpi{80} {\color{Blue} \Theta }$                = tan$\dpi{80} {\color{Blue} \Theta }$
```
10 months ago
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### Course Features

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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions