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How do you solve this? The answer is A ...........................................

How do you solve this? The answer is A
...........................................

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Grade:11

1 Answers

Devang
52 Points
5 years ago
    sin5{\color{Blue} \Theta }  + sin2{\color{Blue} \Theta } – sin{\color{Blue} \Theta } /  cos5{\color{Blue} \Theta } + 2cos3{\color{Blue} \Theta } + 2cos2{\color{Blue} \Theta } + cos{\color{Blue} \Theta }
                = 2 * cos3{\color{Blue} \Theta } * sin2{\color{Blue} \Theta }  + sin2{\color{Blue} \Theta } / 2 * cos3{\color{Blue} \Theta } * cos2{\color{Blue} \Theta } + 2cos3{\color{Blue} \Theta } + 2cos2{\color{Blue} \Theta }
               =  sin2{\color{Blue} \Theta } (2cos3{\color{Blue} \Theta } + 1) / 2cos3{\color{Blue} \Theta } ( cos2{\color{Blue} \Theta } + 1)  + 2cos2{\color{Blue} \Theta }
               =sin2{\color{Blue} \Theta } (2cos3{\color{Blue} \Theta } + 1)  / 2cos3{\color{Blue} \Theta } * 2cos2{\color{Blue} \Theta }  + 2cos2{\color{Blue} \Theta }                         (1 + cos2{\color{Blue} \Theta } = 2cos2{\color{Blue} \Theta } )
               =sin2{\color{Blue} \Theta } (2cos3{\color{Blue} \Theta } + 1)  /  2cos2{\color{Blue} \Theta }  (2cos3{\color{Blue} \Theta } + 1)
               = 2 * sin {\color{Blue} \Theta } * cos{\color{Blue} \Theta } /  2cos2{\color{Blue} \Theta } 
               = tan{\color{Blue} \Theta } 
 

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