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Given is A+B+C=0 then what is the value of sinA+sinB+sinC= a)-2sinA/2 sinB/2 sinC/2 b)-4sinA/2 sinB/2 sinC/2
Given is A+B+C=0 then what is the value of sinA+sinB+sinC= a)-2sinA/2 sinB/2 sinC/2b)-4sinA/2 sinB/2 sinC/2

```
2 years ago

Susmita
425 Points
```							A+B+C=0Or,A=-(B+C)sinA+sinB+sinC=-sin(B+C)+sinB+sinC=-sinBcosC-sinCcosB+sinB+sinC=sinB(1-cosC)+sinC(1-cosB)=sinB.2sin2(C/2)+sinC.2sin2(B/2)=2sin(B/2)cos(B/2).2sin2(C/2)+2sin(C/2)cos(C/2l.2sin2(B/2)=4sin(B/2)sin(C/2)[cos(B/2)sin(C/2)+cos(C/2)sin(B/2)]=4sin(B/2)sin(C/2)sin{(B+C)/2}=-4sin(B/2)sin(C/2)sin(A/2)If it helps please approve.
```
2 years ago
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### Course Features

• 31 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions