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Given: [1/(cos1*cos0)]*[1/(cos1*cos2)]*......so on.....*[1/(cos88*cos89)]=kcos1 Find the value of k?

Given:
[1/(cos1*cos0)]*[1/(cos1*cos2)]*......so on.....*[1/(cos88*cos89)]=kcos1
 
Find the value of k?

Grade:11

1 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
one year ago
Dear student

Please find the link attached

https://www.askiitians.com/forums/Trigonometry/what-is-the-value-of-cos0-x-cos1-x-cos2-x_196137.htm

Kindly check the question

Regards

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