Given: [1/(cos1*cos0)]*[1/(cos1*cos2)]*......so on.....*[1/(cos88*cos89)]=kcos1 Find the value of k?

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Saurabh Koranglekar · Answer

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Given: [1/(cos1cos0)][1/(cos1cos2)]......so on.....[1/(cos88cos89)]=kcos1 Find the value of k?

Given:
[1/(cos1cos0)][1/(cos1cos2)]......so on.....[1/(cos88cos89)]=kcos1

Find the value of k?

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Given: [1/(cos1*cos0)]*[1/(cos1*cos2)]*......so on.....*[1/(cos88*cos89)]=kcos1 Find the value of k?

Given:[1/(cos1*cos0)]*[1/(cos1*cos2)]*......so on.....*[1/(cos88*cos89)]=kcos1 Find the value of k?

1 Answers

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Given: [1/(cos1cos0)][1/(cos1cos2)]......so on.....[1/(cos88cos89)]=kcos1 Find the value of k?

Given:
[1/(cos1cos0)][1/(cos1cos2)]......so on.....[1/(cos88cos89)]=kcos1

Find the value of k?