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general solutions of sinx cosx and tanx

siddharth chandil , 11 Years ago
Grade 12
anser 3 Answers
Rinkoo Gupta
sinxcosx=1/2.2sinxcox=(sin2x)/2

-1=sin2x=1

-1/2=(sin2x)/2=1/2

-infinity=tanx=infinty

Thanks & Regards

Rinkoo Gupta

AskIITians Faculty

Last Activity: 11 Years ago
Arun Kumar
Hi

Arun Kumar, IIT delhi, Btech, Askiitians Faculty
ApprovedApproved
Last Activity: 11 Years ago
Rinkoo Gupta
sinxcosx=(1/2).2sinxcosx=(sin2x)/2
-1=or<sin2x< or = 1
-1/2 = or < (sin2x)/2<or = 1/2
-infinityor =<tanx< or = infinity
Thanks & Regards
Rinkoo Gupta
AskIITians Faculty
Last Activity: 11 Years ago
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