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siddharth chandil Grade: 12
        
general solutions of sinx cosx and tanx
3 years ago

Answers : (3)

Rinkoo Gupta
askIITians Faculty
80 Points
										sinxcosx=1/2.2sinxcox=(sin2x)/2

-1=sin2x=1

-1/2=(sin2x)/2=1/2

-infinity=tanx=infinty

Thanks & Regards

Rinkoo Gupta

AskIITians Faculty

3 years ago
Arun Kumar
IIT Delhi
askIITians Faculty
256 Points
										Hi

Arun Kumar, IIT delhi, Btech, Askiitians Faculty
3 years ago
Rinkoo Gupta
askIITians Faculty
80 Points
										sinxcosx=(1/2).2sinxcosx=(sin2x)/2
-1=or<sin2x< or = 1
-1/2 = or < (sin2x)/2<or = 1/2
-infinityor =<tanx< or = infinity
Thanks & Regards
Rinkoo Gupta
AskIITians Faculty
3 years ago
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