MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

⇐ BackProceed to Checkout ⇒
There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass 
        For what value of k, does the following system of equations have a solution?x+y+z=1, x+2y+4z=k, x+4y+10z=k^2
one year ago

Answers : (1)

Nishant Vora
IIT Patna
askIITians Faculty
2468 Points 
							The system of linear equations have a solution means either it can have uniques soln or infinite soln

If we go according to cramer’s rule,

here D=0

So solution can not be unique it can be infinite only

Hence D1=D2=D3 =0 will be condition. Now solve for this conditions and find values of k

That’s it!
one year ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Other Related Questions on Trigonometry

Solve the equation: sin^4 x + cos^2 x= 2sin 4x.cos^4 x Answer & Earn Cool Goodies
prove that the general solution of the equation ( cos 3x – sin 3x) 2 = sin 2x + 1 is ( 2n + 1)* pi/4 Answer & Earn Cool Goodies
aeroplane flying horizontally 1km above the ground is observed at an elevation of 60 o .If after 10...
a sample of h-like ion is in a particular excited state n2. the electron in it makes back transition...
Solve the following question Prove that- b² cos2A - a² cos2B = b²-a²
View all Questions »

Get Extra Rs. 1,590 off

COUPON CODE: SELF10


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 31 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Get Extra Rs. 64 off

COUPON CODE: SELF10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers To Win!!! Click Here for details