MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

⇐ BackProceed to Checkout ⇒
There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass 
        For what value of k, does the following system of equations have a solution?x+y+z=1, x+2y+4z=k, x+4y+10z=k^2
2 years ago

Answers : (1)

Nishant Vora
IIT Patna
askIITians Faculty
2468 Points 
							The system of linear equations have a solution means either it can have uniques soln or infinite soln

If we go according to cramer’s rule,

here D=0

So solution can not be unique it can be infinite only

Hence D1=D2=D3 =0 will be condition. Now solve for this conditions and find values of k

That’s it!
2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Other Related Questions on Trigonometry

the mean and the standard deviation of a data of 8 items are 25 and 5 respectively. If two items 15... Answer & Earn Cool Goodies
I n a triangle if r:r 1 :R = 2:12:5 then prove that triangle is right angled which is not isosceles.... Answer & Earn Cool Goodies
Prove That tan70-tan20=2tan50 Ans I need plz help me
If Sinx+cosx=√2tanx then what is the value of tanx and how can we solve this problem
Which rational number should be the correct value of √3cot20 - 4 cos20
View all Questions »


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 31 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers To Win!!! Click Here for details