MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

⇐ BackProceed to Checkout ⇒
There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass 
        For what value of k, does the following system of equations have a solution?x+y+z=1, x+2y+4z=k, x+4y+10z=k^2
2 years ago

Answers : (1)

Nishant Vora
IIT Patna
askIITians Faculty
2468 Points 
							The system of linear equations have a solution means either it can have uniques soln or infinite soln

If we go according to cramer’s rule,

here D=0

So solution can not be unique it can be infinite only

Hence D1=D2=D3 =0 will be condition. Now solve for this conditions and find values of k

That’s it!
2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

Other Related Questions on Trigonometry

a tanA+b tanB =[a+b]tan{B+C/2} THEN COMMENT ABOUT THE TRIANGLE ABC {A}right angled {b}equilateral... Answer & Earn Cool Goodies
Please solve this question quickly. I am confused whether we should proceed with the tan formula or... Answer & Earn Cool Goodies
(1+cosπ/8)( 1+cos3π/8)( 1+cod 5π/8)(1+cos7π/8) prove that it is1/2
TanA+sinA=m and tanA_sinA=n show that (m^2-n^2)=16mn
Find the general solution of the equation of the equation cos3x_sinx=cos5x
View all Questions »


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 31 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers To Win!!! Click Here for details