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For what value of k, does the following system of equations have a solution?x+y+z=1, x+2y+4z=k, x+4y+10z=k^2

For what value of k, does the following system of equations have a solution?x+y+z=1, x+2y+4z=k, x+4y+10z=k^2

Grade:12th pass

1 Answers

Nishant Vora IIT Patna
askIITians Faculty 2467 Points
5 years ago
The system of linear equations have a solution means either it can have uniques soln or infinite soln

If we go according to cramer’s rule,

here D=0

So solution can not be unique it can be infinite only

Hence D1=D2=D3 =0 will be condition. Now solve for this conditions and find values of k

That’s it!

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