Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
For what value of k, does the following system of equations have a solution?x+y+z=1, x+2y+4z=k, x+4y+10z=k^2 For what value of k, does the following system of equations have a solution?x+y+z=1, x+2y+4z=k, x+4y+10z=k^2
The system of linear equations have a solution means either it can have uniques soln or infinite solnIf we go according to cramer’s rule,here D=0So solution can not be unique it can be infinite onlyHence D1=D2=D3 =0 will be condition. Now solve for this conditions and find values of kThat’s it!
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -