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Find the value of sin2π/7+sin4π/7+sin8π/7. Sir please help me out to do this question

Find the value of sin2π/7+sin4π/7+sin8π/7.
Sir please help me out to do this question

Grade:12th pass

1 Answers

Sudha Haran
36 Points
5 years ago
=sin2π/7+sin4π/7+sin8π/7=sin2π/7+sin3π7+sinπ/7=sinπ/7+sin2π/7+sin3π/7Now use formula of the continues series of Trigonometric equation=(sin3π/14*sin4π/14)/sinπ/14=(sinπ/2-sinπ/2)/2sinπ/14. =0

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