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Evaluate the value of (1+cosπ/8) (1+cos3π/8) (1+cos5π/8) (1+cos7π/8)

Evaluate the value of (1+cosπ/8) (1+cos3π/8) (1+cos5π/8) (1+cos7π/8) 

Grade:9

3 Answers

Arun
25750 Points
4 years ago
cos 5pi/8=cos(pi/2+pi/8)=-sin pi/8
cos 3pi/8=cos(pi/2-pi/8)=sin pi/8
cos 7pi/8=cos(pi-pi/8)=-cos pi/8. Now the expression (1+cos pi/8)(1+cos 3pi/8)(1+cos 5pi/8)(1+cos 7pi/8) can be written as,
(1+cos pi/8)(1+sin pi/8)(1-sin pi/8)(1-cos pi/8)
=[1-(cos pi/8)^2][1–(sin pi/8)^2]
=(sin pi/8)^2×(cos pi/8)^2
=1/4×(2 sin pi/8.cos pi/8)^2
=1/4(sin 2x pi/8)^2
=1/4(sin pi/4)^2
=1/4×1/[(2)^1/2]^2
=1/4×1/2
=1/8(proven)
 
Saurabh Koranglekar
askIITians Faculty 10335 Points
4 years ago
576-1938_IMG_20200422_152538.jpg
Vikas TU
14149 Points
3 years ago
Dear student 
Hope your doubt gets cleared 
Please refer the solved examples of the below link 

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