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Evaluate: (i) (sin^2 63° + sin^2 27°)/(cos^2 17° + cos^2 73°) Evaluate: (i) (sin^2 63° + sin^2 27°)/(cos^2 17° + cos^2 73°)
Dear Student(sin^2 63° + sin^2 27°)/(cos^2 17° + cos^2 73°)To simplify this,convert some of the sin functions into cos functions and cos function into sin function and it becomes,= [sin^2 (90°-27°) + sin^2 27°]/[cos^2 (90°-73°) + cos^2 73°)] = (cos^2 27° + sin^2 27°)/(sin^2 73° + cos^2 73°)since, sin^2 A + cos^2 A = 1= 1/1=1Hence, 1 is the correct answer.Thanks
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