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Grade: 12

                        

Evaluate: (i) (sin^2 63° + sin^2 27°)/(cos^2 17° + cos^2 73°)

one month ago

Answers : (1)

Anand Kumar Pandey
askIITians Faculty
1677 Points
							Dear Student

(sin^2 63° + sin^2 27°)/(cos^2 17° + cos^2 73°)
To simplify this,
convert some of the sin functions into cos functions and cos function into sin function and it becomes,

= [sin^2 (90°-27°) + sin^2 27°]/[cos^2 (90°-73°) + cos^2 73°)] = (cos^2 27° + sin^2 27°)/(sin^2 73° + cos^2 73°)
since, sin^2 A + cos^2 A = 1
= 1/1
=1
Hence, 1 is the correct answer.
Thanks
one month ago
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