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Evaluate: (i) (sin^2 63° + sin^2 27°)/(cos^2 17° + cos^2 73°)

Evaluate: (i) (sin^2 63° + sin^2 27°)/(cos^2 17° + cos^2 73°)

Grade:12

1 Answers

Harshit Singh
askIITians Faculty 5963 Points
3 years ago
Dear Student

(sin^2 63° + sin^2 27°)/(cos^2 17° + cos^2 73°)
To simplify this,
convert some of the sin functions into cos functions and cos function into sin function and it becomes,

= [sin^2 (90°-27°) + sin^2 27°]/[cos^2 (90°-73°) + cos^2 73°)] = (cos^2 27° + sin^2 27°)/(sin^2 73° + cos^2 73°)
since, sin^2 A + cos^2 A = 1
= 1/1
=1
Hence, 1 is the correct answer.
Thanks

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