Differentiate x/sqr.root x2+a2. In the solution the denominator is taken up with negative power . and why is it that in differentiation of x2+a2 , a2 is taken 0 ?

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Nikitha · Answer

Because a is a constant and square of a constant term is also a constant. And differentiation of a constant term is zero.

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Differentiate x/sqr.root x2+a2. In the solution the denominator is taken up with negative power . and why is it that in differentiation of x2+a2 , a2 is taken 0 ?

Differentiate x/sqr.root x2+a2. In the solution the denominator is taken up with negative power . and why is it that in differentiation of x2+a2 , a2 is taken 0 ?

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Differentiate x/sqr.root x2+a2. In the solution the denominator is taken up with negative power . and why is it that in differentiation of x2+a2 , a2 is taken 0 ?

Differentiate x/sqr.root x2+a2. In the solution the denominator is taken up with negative power . and why is it that in differentiation of x2+a2 , a2 is taken 0 ?

1 Answers

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Other Related Questions on Trigonometry

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