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Grade: 12th pass

                        

a sinx + b cos x=root over of A^2+B^2 then find the value of tanx

3 years ago

Answers : (1)

Arun
24737 Points
							
If we divide whole equation by \sqrt(a2 + b2)
We get 
a/\sqrt(a2 + b2) sin x + b/\sqrt(a2 + b2) cos x = 1
 
This is a form of sin(x+\theta) = 1
Where
Cos\theta = a/\sqrt(a2 + b2)
Sin\theta = b/\sqrt(a2 + b2)
so
Tan \LARGE \theta = b/a
 
Hope it clears
3 years ago
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