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a sinx + b cos x=root over of A^2+B^2 then find the value of tanx

a sinx + b cos x=root over of A^2+B^2 then find the value of tanx

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Grade:12th pass

1 Answers

Arun
25763 Points
4 years ago
If we divide whole equation by \sqrt(a2 + b2)
We get 
a/\sqrt(a2 + b2) sin x + b/\sqrt(a2 + b2) cos x = 1
 
This is a form of sin(x+\theta) = 1
Where
Cos\theta = a/\sqrt(a2 + b2)
Sin\theta = b/\sqrt(a2 + b2)
so
Tan \LARGE \theta = b/a
 
Hope it clears

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