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a sinx + b cos x=root over of A^2+B^2 then find the value of tanx
If we divide whole equation by (a2 + b2)We get a/(a2 + b2) sin x + b/(a2 + b2) cos x = 1 This is a form of sin(x+) = 1WhereCos = a/(a2 + b2)Sin = b/(a2 + b2)soTan = b/a Hope it clears
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