a sinx + b cos x=root over of A^2+B^2 then find the value of tanx

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Arun · Answer

If we divide whole equation by (a 2 + b 2 ) We get a/ (a 2 + b 2 ) sin x + b/ (a 2 + b 2 ) cos x = 1 This is a form of sin(x+ ) = 1 Where Cos = a/ (a 2 + b 2 ) Sin = b/ (a 2 + b 2 ) so Tan = b/a Hope it clears

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a sinx + b cos x=root over of A^2+B^2 then find the value of tanx

a sinx + b cos x=root over of A^2+B^2 then find the value of tanx

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